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07/03/2012 - C.Sreeves vs A.Burnett
#68
27...Qxe6 obviously forced.
[pgn]1. c4 e5 2. g3 Nc6 3. Nc3 g6 4. Bg2 Bg7 5. d3 d6 6. e4 h5 7. h4 Nd4 8. Nce2 Ne6 9. Nf3 Nf6 10. O-O a5 11. b3 O-O 12. a3 c6 13. Bb2 c5 14. Bc3 Nd4 15. Nexd4 exd4 16. Bd2 Ng4 17. b4 axb4 18. axb4 Rxa1 19. Qxa1 f5 20. Ng5 Ne5 21. Qa3 Qe7 22. bxc5 dxc5 23. f4 Ng4 24. e5 Bh6 25. Bd5 Kg7 26. Nf3 Be6 27. Bxe6 Qxe6[/pgn]
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