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Quiz question of the day
#2
6

But that is incredibly unlikely because it would require .........

(a) One the 7 norm chasers to lose all games against the other norm chasers.
(b) each IM and GM to lose all games against those 6 remaining norm chasers.
Which puts 6 norm chasers on 4/4
© Those 6 remaining norm chasers would then need to score 2.5/5 against the other 5. Not necessarily with 15 drawn games though.
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